
Ceq=5μF
Potentialof4μF=6volt
∴chargeon4μF(q4)=24μC
Potential of9μF=2volt
∴chargeon9μF(q9)=18μC
Totalcharge(q)=42μC
E=r2kq=9009×109×42×10−6=420N/C
A combination of capacitors is set up as shown in the figure. The magnitude of the electric field, due to a point charge Q (having a charge equal to the sum of the charges on the 4μF and 9μF capacitors), at a point distant 30 m from it, would equal:

Held on 3 Apr 2016 · Verified 6 Jul 2026.
420 N/C
480 N/C
240 N/C
360 N/C
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