By the property of electrostatic shielding in the conductors E=0 in the conductor. So, electric flux,=0 through a dotted Gaussian surface as shown

The net enclosed charge through the Gaussian surface=0,⇒ The net charge Q1 on the inner surface=0, but the equal and opposite induced charge on the surface will be distributed non uniformly on the inner surface
So, σ1=0
∵Q1=0 on the inner surface
So, net charge Q2=0 on the outer surface as conductor is neutral but ∵ outer surface is free from any electric field so no charge density exists on the outer surface. So, σ2=0 .
