Case I: K1 is closed for long time,

for a long time, the inductor acts as a conducting wire, ⇒current in the circuit =RV=15015⇒i0=0.1 A
Case II: K1 is open and K2 is closed

Current in the circuit, i=i0eτ−t; τ=RL
After t=1ms=10−3s
⇒i=i0e−(3×10−210−3×150)=0.1e3−15=0.1e51=1500.1A=0.67 mA.