JEE Main 2015 — Physics Electromagnetism
An electromagnetic wave travelling in the x− direction has frequency of 2×1014Hz and electric field amplitude of 27Vm–1 oscillates in Y−direction. From the options given below, which one describes the magnetic field for this wave?
Held on 10 Apr 2015 · Verified 6 Jul 2026.
B(x,t)=(9×10−8T)j^ sin[1.5×10−6x−2×1014t]
B(x,t)=(9×10−8T)i^sin[2π(1.5×10−8x−2×1014t)]
B(x,t)=(3×10−8T)j^sin2π[(1.5×10−8x)−2×1014t]
B(x,t)=(9×10−8T)k^sin2π[(1.5×10−6x)−2×1014t]
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