E=150N/C
We know that ϕ=E⋅A
=E×4πr2
=150×4π×()(Re)()
Now, ϕ=Qin

Qin=ϕ∈o=150×4π()(Re)()×8.85×10C
=150×4π6.37×106×8.85×10
=600π×6.37×6.37×8.85C
=680kC
As Electric field is inward, Q will be negative
JEE Main 2014 — Physics Electromagnetism
The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about 150N/C, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be : [Given : ∈O=8.85×10−12 C2/N-m2, RE=6.37×106m]
Held on 9 Apr 2014 · Verified 6 Jul 2026.
−680kC
+670kC
+680kC
−670kC
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