dC1=ϵ0ϵAdx
=ϵ0[ϵ1+d(ϵ2−ϵ1)x]Adx
C1=∫dC1=∈0A1∫0x∈1+(d∈2−∈1)dx
=∈0A(∈2−∈1)ln(∈2/∈1)d
C=ln(∈2/∈1)⋅d∈0A(∈2−∈1)

JEE Main 2014 — Physics Electromagnetism
The gap between the plates of a parallel plate capacitor of area A and distance between plates d, is filled with a dielectric whose relative permittivity varies linearly from ϵ1 at one plate to ϵ2 at the other. The capacitance of the capacitor is
Held on 19 Apr 2014 · Verified 6 Jul 2026.
[dln(∈2/∈1)]ϵ0(∈2−∈1)A
2dϵ0(∈2+∈1)A
dϵ0(∈1+∈2)A
[dln(∈2/∈1)]ϵ0A
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