In steady state capacitor is fully charged hence no current will flow through line 2. By simplyfing the circuit
Hence resultant potential difference across resistances will be 8.0 V. Thus current I=RV=3+98.0=128 or, I=32=0.67 A
The circuit shown here has two batteries of 8.0 ~V and 16.0 ~V and three resistors 3 Ω, 9 Ω and 9 Ω and a capacitor of 5.0 μ F. JEE Main 2014…
JEE Main 2014 — Physics Electromagnetism
2014mcqmedium
The circuit shown here has two batteries of 8.0 V and 16.0 V and three resistors 3Ω,9Ω and 9Ω and a capacitor of 5.0μF. 
How much is the current I in the circuit in steady state?
Official previous-year question
Held on 12 Apr 2014 · Verified 6 Jul 2026.
Options
- A
1.6 A
- B
0.67 A
- C
2.5 A
- D
0.25 A
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