Match List I (Wavelength range of electromagnetic spectrum) with List II (Method of production of these waves) and select the correct option from the options given below the lists. List I List II (a) $700\mathrm{nm}$ to $1\mathrm{mm}$ (i) Vibration of atoms and molecules. (b) $1\mathrm{nm}$ to $400\mathrm{nm}$ (ii) Inner shell electrons in atoms moving from one energy level to a lower level. (c) $ (iii) Radioactive decay of the nucleus. (d) $1\mathrm{mm}$ to $0.1m$ (iv) Magnetron valve.

JEE Main 2014 — Physics Electromagnetism

2014mcqeasy

Match List I (Wavelength range of electromagnetic spectrum) with List II (Method of production of these waves) and select the correct option from the options given below the lists.

	List I		List II
(a)	$700\mathrm{nm}$ to $1\mathrm{mm}$	(i)	Vibration of atoms and molecules.
(b)	$1\mathrm{nm}$ to $400\mathrm{nm}$	(ii)	Inner shell electrons in atoms moving from one energy level to a lower level.
(c)	$<{10}^{-3}\mathrm{nm}$	(iii)	Radioactive decay of the nucleus.
(d)	$1\mathrm{mm}$ to $0.1m$	(iv)	Magnetron valve.

Official previous-year question

Held on 9 Apr 2014 · Verified 6 Jul 2026.

Options

A
(a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
B
(a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
C
(a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)
D
(a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

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Solution

We know, the range of wavelengths between $700\mathrm{nm}\text{ to}1\mathrm{mm}$ , is referred as Infrared rays. These are produced by heating an object to such an extent that the molecules start vibrating and it radiates infrared waves. When the object is not hot enough such that it can emit visible light, therefore, it radiates Infrared waves.

Thus, option (a) in list I matches with Option (i) in list II.

The range of wavelengths between $1\mathrm{nm}\text{ to}400\mathrm{nm}$ , is referred to as ultraviolet rays. Ultraviolet rays are produced due to atomic excitation in a gaseous discharge tube. This atomic excitation occurs when an atom from one energy level jumps to a lower energy level.

Thus, option (b) in list I matches with Option (ii) in list II.

The range of wavelengths $<{10}^{-3}\mathrm{nm}$ are known as the Gamma rays. Some of the radioactive substances, when decay releases a spectrum, which falls in the range of $<{10}^{-3}\mathrm{nm}$ , they emit electromagnetic waves called the gamma rays.

Thus, we can say, Thus, option (c) in list I matches with Option (iii) in list II.

We know again, the range of wavelength $1\mathrm{mm}\text{ to}0.1m$ , is referred to as microwaves, and they are produced inside an oven in a tube like structure, called the magnetron.

Thus, we can say, option (d) in list I matches with Option (iv) in list II.

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List I

List II

(a)

700\mathrm{nm}

1\mathrm{mm}

(i)

Vibration of atoms and molecules.

(b)

1\mathrm{nm}

400\mathrm{nm}

(ii)

Inner shell electrons in atoms moving from one energy level to a lower level.

(c)

<{10}^{-3}\mathrm{nm}

(iii)

Radioactive decay of the nucleus.

(d)

1\mathrm{mm}

0.1m

(iv)

Magnetron valve.

Solution

Thus, option (a) in list I matches with Option (i) in list II.

Thus, option (b) in list I matches with Option (ii) in list II.

Thus, we can say, Thus, option (c) in list I matches with Option (iii) in list II.

We know again, the range of wavelength $1\mathrm{mm}\text{ to}0.1m$ , is referred to as microwaves, and they are produced inside an oven in a tube like structure, called the magnetron.

Thus, we can say, option (d) in list I matches with Option (iv) in list II.

JEE Main 2014 — Physics Electromagnetism

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Solution

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JEE Main 2014 — Physics Electromagnetism

Options

Did you get this right?

Solution

Your note

JEE Main Electromagnetism in other years

More JEE Main Electromagnetism questions

Other Physics topics for JEE Main

Mechanics

Modern Physics

Optics

Thermodynamics

Waves & Oscillations

Keep practicing Electromagnetism