E=3×104 V/m
We know that
Q=CV
=dkϵ0A⋅E⋅d
=kϵ0AE
AQ=kϵ0E
=2.2×8.85×10−12×3×104
=58.41×10−8
=5.84×10−7
≈6×10−7C/m2
JEE Main 2014 — Physics Electromagnetism
A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3×104 V/m, the charge density of the positive plate will be close to :
Held on 6 Apr 2014 · Verified 6 Jul 2026.
6×10−7 C/m2
3×10−7 C/m2
3×104 C/m2
6×104 C/m2
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