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Two small equal point charges of magnitude q are suspended from a common point on the ceiling by insulating mass less strings of equal lengths. They…

JEE Main 2013 — Physics Electromagnetism

2013mcqhard

Two small equal point charges of magnitude qqq are suspended from a common point on the ceiling by insulating mass less strings of equal lengths. They come to equilibrium with each string making angle θ\thetaθ from the vertical. If the mass of each charge is mmm, then the electrostatic potential at the centre of line joining them will be (14π∈0=k). \left(\frac{1}{4 \pi \in_0}=k\right) \text {. }(4π∈0​1​=k). 

Official previous-year question

Held on 22 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    2kmgtan⁡θ2 \sqrt{k m g \tan \theta}2kmgtanθ​

  2. B

    kmgtan⁡θ\sqrt{k m g \tan \theta}kmgtanθ​

  3. C

    4kmg/tan⁡θ4 \sqrt{k m g / \tan \theta}4kmg/tanθ​

  4. D

    4kmg/tan⁡θ4 \sqrt{k m g / \tan \theta}4kmg/tanθ​

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