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The surface charge density of a thin charged disc of radius R is σ. The value of the electric field at the centre of the disc is σ 2 ∈_0. With…

JEE Main 2013 — Physics Electromagnetism

2013mcqeasy

The surface charge density of a thin charged disc of radius R\mathrm{R}R is σ\sigmaσ. The value of the electric field at the centre of the disc is σ2∈0\frac{\sigma}{2 \in_0}2∈0​σ​. With respect to the field at the centre, the electric field along the axis at a distance R\mathrm{R}R from the centre of the disc:

Official previous-year question

Held on 25 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    reduces by 70.7%70.7 \%70.7%

  2. B

    reduces by 29.3%29.3 \%29.3%

  3. C

    reduces by 9.7%9.7 \%9.7%

  4. D

    reduces by 14.6%14.6 \%14.6%

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