Since particle is moving undeflected So, qE=qvB ⇒B=VE=10104=103wb/m2
A particle of charge 16 × 10^-16 C moving with velocity 10 ~ms^-1 along x-axis enters a region where magnetic field of induction B is along the…
JEE Main 2013 — Physics Electromagnetism
A particle of charge 16×10−16C moving with velocity 10 ms−1 along x-axis enters a region where magnetic field of induction B is along the y-axis and an electric field of magnitude 104Vm−1 is along the negative z-axis. If the charged particle continues moving along x-axis, the magnitude of B is :
Held on 23 Apr 2013 · Verified 6 Jul 2026.
Options
- A
16×103 Wb m−2
- B
2×103 Wb m−2
- C
1×103 Wb m−2
- D
4×103 Wb m−2
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