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Let P(r)= Q π R^4 r be the charge density distribution for a solid sphere of radius R and total charge Q. for a point ' p ' inside the sphere at…

JEE Main 2009 — Physics Electromagnetism

2009mcqhard

Let P(r)=QπR4rP(r)=\frac{Q}{\pi R^4} rP(r)=πR4Q​r be the charge density distribution for a solid sphere of radius RRR and total charge QQQ. for a point ' ppp ' inside the sphere at distance r1r_1r1​ from the centre of the sphere, the magnitude of electric field is

Official previous-year question

Held on 30 Apr 2009 · Verified 6 Jul 2026.

Options

  1. A

    0

  2. B

    Q4πε0r12\frac{Q}{4 \pi \varepsilon_0 r_1^2}4πε0​r12​Q​

  3. C

    Qr124πε0R4\frac{Q r_1^2}{4 \pi \varepsilon_0 R^4}4πε0​R4Qr12​​

  4. D

    Q123πε0R4\frac{Q_1^2}{3 \pi \varepsilon_0 R^4}3πε0​R4Q12​​

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