Let resistances be R1 and R2 So, S=R1+R2; P=R1+R2R1R2 S=nPR1+R2=R1+R2nR1R2(R1+R2)2=nR1R2 If R1=R2, so minimum value of n=4.
JEE Main 2004 — Physics Electromagnetism
The resistance of the series combination of two resistances is S. When they are joined in parallel through total resistance is P. If S=nP, then the minimum possible value of n is
Held on 30 Apr 2004 · Verified 6 Jul 2026.
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