The formula of de-Broglie wavelength, λ=2mK.E.h and we know that, K.E.=eV. Recall the proper relation between wavelength and electric potential, in angstrom, λ=V12.27A˚=14412.27×10−10=1.02×10−10m
it means the wavelength, λ=102×10−3nm.
The de-Broglie wavelength of an electron moving with kinetic energy of 144eV is nearly
Held on 30 Apr 2020 · Verified 9 Jul 2026.
102×10−3nm
102×10−4nm
102×10−5nm
102×10−2nm
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