Wave velocity in string: v=μT
Time to reach joint: t=vL=LTμ
t1=LATμA and t2=LBTμB
t2t1=LBLA×μBμA=1.52.5×4×10−42×10−4
=35×21=325=652≈1.18
Two strings (A, B) having linear densities μ_A=2 × 10^-4 ~kg / m and, μ_B=4 × 10^-4 ~kg / m and lengths L_A=2.5 ~m and L_B=1.5 ~m respectively are…
JEE Main 2026 — Physics Waves & Oscillations
2026mcqmedium
Two strings (A,B) having linear densities μA=2×10−4 kg/m and, μB=4×10−4 kg/m and lengths LA=2.5 m and LB=1.5 m respectively are joined. Free ends of A and B are tied to two rigid supports C and D, respectively creating a tension of 500 N in the wire. Two identical pulses, sent from C and D ends, take time t1 and t2, respectively, to reach the joint. The ratio t1/t2 is :
Official previous-year question
Held on 21 Jan 2026 · Verified 6 Jul 2026.
Options
- A
1.90
- B
1.67
- C
1.08
- D
1.18
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