Point B will 10th maxima
Δx=L2B−L1B
L1B=202+402=205 m=44.6 m
L2B=402+302=50 m
Δx=50−44.6=5.4 m
Δx=nλ
5.4=10×λ
λ=0.54 m
V=fλ
f=0.54324=600 Hz
JEE Main 2026 — Physics Waves & Oscillations
2026integermedium
Two loudspeakers (L1 and L2) are placed with a separation of 10 m, as shown in figure. Both speakers are fed with an audio input signal of same frequency with constant volume. A voice recorder, initially at point A, at equidistance to both loud speakers, is moved by 25 m along the line AB while monitoring the audio signal. The measured signal was found to undergo 10 cycles of minima and maxima during the movement. The frequency of the input signal is ____ Hz (Speed of sound in air is 324 m/s and 5=2.23)
Official previous-year question
Held on 22 Jan 2026 · Verified 6 Jul 2026.
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