The given equation is v2=50−x2
Differentiating with respect to x:
2vdxdv=−2x
vdxdv=−x
Since acceleration a=vdxdv, we get:
a=−x
Comparing this with the standard equation of SHM a=−ω2x, we get:
ω2=1⇒ω=1 rad/s
The time period of the motion is given by:
T=ω2π=2π
Taking π=722, we get:
T=2×722=744 s
Given that the time period is 7x s, comparing the two gives:
x=44
Answer: 44