The equation of simple harmonic motion for a particle starting from the extreme position x=A is given by:
x=Acos(ωt)
We need to find the time t when the particle reaches x=2A. Substituting this value into the equation:
2A=Acos(ωt)
cos(ωt)=21
ωt=4π
Since the angular frequency ω=T2π, we have:
T2πt=4π
t=8T
Given the time period T=5 sec, the required time is:
t=85 sec
Answer: 5/8