$\begin{aligned}
& g=\frac{G M}{R^2} \
& g^{\prime}=\frac{G(4 M)}{(2 R)^2}=g
\end{aligned}Aiscorrect,Riscorrect;butsinceT=2 \pi \sqrt{\frac{\ell}{g}}$ doesn't depend on mass ; R doesn't explain A .
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : A simple pendulum is taken…
JEE Main 2025 — Physics Waves & Oscillations
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : A simple pendulum is taken to a planet of mass and radius, 4 times and 2 times, respectively, than the Earth. The time period of the pendulum remains same on earth and the planet. Reason (R): The mass of the pendulum remains unchanged at Earth and the other planet. In the light of the above statements, choose the correct answer from the options given below :
Held on 22 Jan 2025 · Verified 6 Jul 2026.
Options
- A
(A) is false but (R) is true
- B
(A) is true but (R) is false
- C
Both (A) and (R) are true and (R) is the correct explanation of (A)
- D
Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
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