$\begin{aligned}
& \mathrm{v}=\frac{\text { distance }}{\text { time }} \
& \mathrm{v}=\frac{12}{0.3}=4 \mathrm{~cm} / \mathrm{s} \
& \mathrm{k}=\frac{2 \pi}{\lambda}=\frac{2 \pi}{7.5}=\frac{4 \pi}{15}=0.83 \
& \mathrm{v}=\frac{\omega}{\mathrm{k}} \Rightarrow \omega=\mathrm{vk}=4 \times \frac{4 \pi}{15}=3.35
\end{aligned}$
So y=Acos(kx−ωt)