From $y = 5\sin(\omega t - kx)$: $\omega = 100\pi$, $k = 0.4\pi$
$$v = \frac{\omega}{k} = \frac{100\pi}{0.4\pi} = 250\,\text{cm/s}$$
Back to JEE Main 2024 Waves & Oscillations
JEE Main 2024 — Physics Waves & Oscillations
hard
mcq
2024
Official previous-year question
Verified 30 May 2026.
Question
The equation of a progressive wave is $y = 5\sin(100\pi t - 0.4\pi x)$ where $y$ and $x$ are in cm and $t$ in seconds. The velocity of the wave is:
Options
- A
$250\,\text{cm/s}$
- B
$500\,\text{cm/s}$
- C
$100\,\text{cm/s}$
- D
$400\,\text{cm/s}$
Solution
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