Acceleration due to gravity at surface of earth, g=R2GM.
Now, at distance R from the surface of the earth, g′=(R+R)2GM=4g
Therefore,
T=2π4gl
⇒T=2πg4×4
⇒T=2ππ4=8s
A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4m, then the time period of small oscillations will be _________s.
[take g=π2ms−2]
Held on 30 Jan 2024 · Verified 6 Jul 2026.
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