From phasor diagram particle has to move from P to Q in a circle of radius equal to amplitude of SHM.
cosϕ=A23A=23
⇒ϕ=6π
Now, 6π=ωt
⇒6π=T2πt
⇒6π=6π2πt
⇒t=2π
So, x=2
A simple harmonic oscillator has an amplitude A and time period 6π second. Assuming the oscillation starts from its mean position, the time required by it to travel fromx=A to x=23A will be xπs, where x=_______.
Held on 29 Jan 2024 · Verified 6 Jul 2026.
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