We know $\begin{aligned}
\mathrm{V}{\max } & =\omega \mathrm{A} \quad \text { at mean position } \
& =\frac{2 \pi}{\mathrm{T}} \mathrm{A}=\frac{2 \pi}{\pi} \times 0.06=0.12 \mathrm{~m} / \mathrm{sec} \
\mathrm{V}{\max } & =12 \mathrm{~cm} / \mathrm{sec}
\end{aligned}$