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A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm s^-1. The distance of…

JEE Main 2024 — Physics Waves & Oscillations

2024integermedium

A particle executes simple harmonic motion with an amplitude of 4cm4\mathrm{cm}4cm. At the mean position, velocity of the particle is 10cms−110\mathrm{cm}{s}^{-1}10cms−1. The distance of the particle from the mean position when its speed becomes 5cms−15\mathrm{cm}{s}^{-1}5cms−1 is αcm\sqrt{\alpha }\mathrm{cm}α​cm, where α=\alpha =α=______.

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Held on 27 Jan 2024 · Verified 6 Jul 2026.

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