fB = 256±4 = 260 or 252. Loading with wax decreases fB. If fB=260, new fB<260, beats=|256-fB'|. Since beats increase to 6, fB must be 260 (decreased to 250 gives 6 beats).
JEE Main 2023 — Physics Waves & Oscillations
Two tuning forks A and B produce 4 beats per second. Fork A has frequency 256 Hz. When B is loaded with wax, beats become 6 per second. The frequency of B is:
Verified 30 May 2026.
260 Hz
252 Hz
250 Hz
262 Hz
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