$f_B = 256 \pm 4 = 260$ or $252\,\text{Hz}$
Loading wax decreases $f_B$. If $f_B = 260$, it decreases → more beats. Since beats increased from 4 to 6, $f_B = 260\,\text{Hz}$.
Verified 30 May 2026.
Two tuning forks $A$ and $B$ produce $4$ beats per second. Fork $A$ has frequency $256\,\text{Hz}$. When $B$ is loaded with wax, beats become $6$ per second. The frequency of $B$ is:
$260\,\text{Hz}$
$252\,\text{Hz}$
$250\,\text{Hz}$
$262\,\text{Hz}$
$f_B = 256 \pm 4 = 260$ or $252\,\text{Hz}$
Loading wax decreases $f_B$. If $f_B = 260$, it decreases → more beats. Since beats increased from 4 to 6, $f_B = 260\,\text{Hz}$.
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