In the figure given below. a block of mass M=490g placed on a frictionless table is connected with two springs having same spring constant…
JEE Main 2023 — Physics Waves & Oscillations
2023integerhard
In the figure given below. a block of mass M=490g placed on a frictionless table is connected with two springs having same spring constant (K=2Nm−1). If the block is horizontally displaced through Xm then the number of complete oscillations it will make in 14π seconds will be ______.
Official previous-year question
Held on 31 Jan 2023 · Verified 6 Jul 2026.
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Solution
Both the springs are connected in parallel, therefore
Keq=K+K=2K
Now, time period of spring-block system is given by,
T=2πKeqm=2π2Km
Given here, m=490gm=0.49kg and K=2Nm−1
So, T=2π2×20.49
=2π40049=2π207=107π
Now, number of oscillation in 14π is
N=Ttime=107π14π=20
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