A block of mass 2 kg is attached with two identical springs of spring constant 20Nm^-1 each. The block is placed on a frictionless surface and the…
JEE Main 2023 — Physics Waves & Oscillations
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A block of mass 2kg is attached with two identical springs of spring constant 20Nm−1 each. The block is placed on a frictionless surface and the ends of the springs are attached to rigid supports (see figure). When the mass is displaced from its equilibrium position, it executes a simple harmonic motion. The time period of oscillation is Xπ in SI unit. The value of X is______.
Official previous-year question
Held on 24 Jan 2023 · Verified 6 Jul 2026.
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Solution
When the block is displaced by a distance x, force acting on block due to both springs will be in the same direction. Therefore,
F=−2kx⇒a=−m2kx,
Comparing it witha=−ω2x , we get
ω=m2k=22×20
=20rads−1
Now, T=ω2π=202π=5π
Hence, required value of X=5.
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