Maximum velocity is given by vmax=ωA =mkA
Here, m1k1A1=m2k2A2
⇒50×10−32kA1=100×10−39kA2
⇒2A1=3A2
Thus, ratio of amplitude is A2A1=23=3:2.
Two massless springs with spring constants 2k and 9k, carry 50g and 100g masses at their free ends. These two masses oscillate vertically such that…
JEE Main 2022 — Physics Waves & Oscillations
2022mcqeasy
Two massless springs with spring constants 2k and 9k, carry 50g and 100g masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be :
Official previous-year question
Held on 24 Jun 2022 · Verified 6 Jul 2026.
Options
- A
3:2
- B
1:2
- C
3:1
- D
2:3
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