The fundamental frequency of the closed organ pipe is given by, f0=4lcv.
The frequency of the first overtone of a open organ pipe is given by, f1=2×2lov.
Since,
f0=f1⇒4lcv=lov⇒lo=4×20=80cm.
The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ…
JEE Main 2022 — Physics Waves & Oscillations
2022integereasy
The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20cm. The length of the open organ pipe is _____ cm
Official previous-year question
Held on 25 Jun 2022 · Verified 6 Jul 2026.
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