$T = 2\pi\sqrt{\frac{L}{g}}$
$$T' = 2\pi\sqrt{\frac{1.21L}{g}} = T\sqrt{1.21} = 1.1T$$
Back to JEE Main 2022 Waves & Oscillations
JEE Main 2022 — Physics Waves & Oscillations
medium
mcq
2022
Official previous-year question
Verified 30 May 2026.
Question
A simple pendulum has time period $T$. If its length is increased by $21\%$, the new time period is:
Options
- A
$1.1T$
- B
$1.21T$
- C
$T\sqrt{1.21}$
- D
$T/1.1$
Solution
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