As we know particle velocity, vp=dtdy=(10×2πn)×cos2π(nt−λx)
Therefore, (vp)max=20πn
Now as we know, v=λn
As given in the question,
(vp)max=4v⇒20πn=4λn⇒λ=5π
A longitudinal wave is represented by y=10sin2π(nt−λx)cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to
Held on 29 Jun 2022 · Verified 6 Jul 2026.
2π
5π
π
25π
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