In SHM, velocity of the particle at any displacement, x is given by, v=A2−x2.
Therefore,
⇒3vv=A22−25(A12−25) ⇒A22−25=3×75
⇒A22=700 ⇒A2=700cm
JEE Main 2022 — Physics Waves & Oscillations
A body is performing simple harmonic with an amplitude of 10cm. The velocity of the body was tripled by air Jet when it is at 5cm from its mean position. The new amplitude of vibration is xcm. The value of x is _____ .
Held on 29 Jun 2022 · Verified 6 Jul 2026.
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