Phase difference: $\Delta\phi = \frac{2\pi}{\lambda} \cdot \Delta x = \frac{2\pi}{4} \cdot 1 = \frac{\pi}{2}$
Back to JEE Main 2021 Waves & Oscillations
JEE Main 2021 — Physics Waves & Oscillations
easy
mcq
2021
Official previous-year question
Verified 30 May 2026.
Question
The phase difference between two points separated by $1\,\text{m}$ on a wave of wavelength $4\,\text{m}$ is:
Options
- A
$\frac{\pi}{2}$
- B
$\pi$
- C
$\frac{\pi}{4}$
- D
$2\pi$
Solution
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