Ta=2πKM
Tb=2πK/2M
TaTb=2=x
Consider two identical springs each of spring constant k and negligible mass compared to the mass M as shown. Fig. 1 shows one of them and Fig. 2 shows their series combination. The ratios of time period of oscillation of the two SHM is TaTb=x, where value of x is ______.
(Round off to the Nearest Integer)

Held on 17 Mar 2021 · Verified 6 Jul 2026.
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