fn=2ℓnv=500
fn+1=2ℓ(n+1)v=550
nn+1=1011
Thus, n=10
Thus, ℓ=2fnnv(v=μT)
=2×50010×9×10−4900=10m
A wire having a linear mass density 9.0×10−4kgm−1 is stretched between two rigid supports with a tension of 900N. The wire resonates at a frequency of 500Hz. The next higher frequency at which the same wire resonates is 550Hz. The length of the wire is ___________ m.
Held on 31 Aug 2021 · Verified 6 Jul 2026.
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