
Applying work energy theorem:
wg+wT=ΔK
−mgl(1−cos60∘)=21mv2−21mu2
v2=u2−2gl(1−cos60∘)
v2=9−2×10×0.5(21)
v2=4
v=2ms−1
A pendulum bob has a speed of 3ms−1 at its lowest position. The pendulum is 50cm long. The speed of bob, when the length makes an angle of 60∘ to the vertical will be (g=10ms−2) ______ ms−1.
Held on 25 Jul 2021 · Verified 6 Jul 2026.
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Work through every JEE Main Waves & Oscillations PYQ, year by year.