From graph equation of SHM.
X=Acosωt
(A) at 43T particle at mean position
∴a=0
F=0
(B) at T particle again at extreme position so acceleration is maximum
(C) at t=4T, particle is at mean position so velocity maximum. ∴a=0
(D) KE=PE
21k(A2−x2)=21kx2
A2=2x2
x=2+A
2A=Acosωt
t=8T
∴A,B and C are correct.