at 0∘C
y=Asin(1000t−3x)
v1=kω=31000
at temperature T,v2=336m/s
v2v1=T2T1
⇒3361000=T273⇒T=277.41K
i.e.T=4.4∘C=4∘C
The pressure wave, P=0.01 sin[1000t-3x]N m^–2 , corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is 0°C…
JEE Main 2019 — Physics Waves & Oscillations
2019mcqmedium
The pressure wave, P=0.01sin[1000t−3x]Nm–2 , corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is 0∘C . On some other day when temperature is T , the speed of sound produced by the same blade and at the same frequency is found to be 336ms–1 . Approximate value of T is:
Official previous-year question
Held on 9 Apr 2019 · Verified 6 Jul 2026.
Options
- A
12∘C
- B
15∘C
- C
4∘C
- D
11∘C
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