For rod A, f1=2ln1ρA1T
For rod B, f2=2ln2ρA2T
Given f1=f2
2ln1ρA1T=2ln2ρA2T
2ln1ρA1T=2ln2ρ(4A1)T[∵rB=2rAA2=4A1]
n1=2n2
n2n1=21
A wire of length 2L, is made by joining two wires A and B of same length but different radii r and 2r and made of the same material. It is vibrating at a frequency such that the joint of the two wires forms a node. If the number of antinodes in wire A is p and that in B is q then ratio p:q is:

Held on 8 Apr 2019 · Verified 6 Jul 2026.
3:5
4:9
1:4
1:2
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