Angular frequency of pendulum ω=ℓg ∴ relative change in angular frequency ωΔω=21gΔg[ as length remains constant ] Δg=2 Aωs2[ωs= angular frequency of support and, A= amplitude] ωΔω=21× g2 AωS2 Δω=21×102×12×10−2=10−3rad/sec
A simple pendulum of length 1 ~m is oscillating with an angular frequency 10 rad / s. The support of the pendulum starts oscillating up and down with…
JEE Main 2019 — Physics Waves & Oscillations
2019mcqhard
A simple pendulum of length 1 m is oscillating with an angular frequency 10rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1rad/s and an amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by :
Official previous-year question
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
10−3rad/s
- B
1rad/s
- C
10−1rad/s
- D
10−5rad/s
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