v=ω52−42=3ω
a=ω2×4
∣a∣=∣v∣
4ω2=3ω
ω=43=T2π
T=38πsec
A particle executes simple harmonic motion with an amplitude of 5cm . When the particle is at 4cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
Held on 10 Jan 2019 · Verified 6 Jul 2026.
38π
83π
34π
37π
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