T=2πgl
T∝l
l=1
TΔT=21lΔl
Δl=r1−r2⇒Δl=T2ΔT×l
=22×5×10−4×1m
=5×10−2cm
=0.05cm
JEE Main 2017 — Physics Waves & Oscillations
In an experiment to determine the period of a simple pendulum of length 1m, it is attached to different spherical bobs of radii r1 and r2 . The two spherical bobs have uniform mass distribution. If the relative difference in the periods, is found to be 5×10−4s, the difference in radii, ∣r1−r2∣ is best-given by
Held on 9 Apr 2017 · Verified 6 Jul 2026.
0.01cm
0.05cm
0.5cm
1cm
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