Given ω=25rad/s and A = 1.6 cm
∴ω=mk=25 ⇒k=252
Maximum compression in the spring
=xo+A
=kmg+A
∴Fmax=4g+k(x0+A)
Fmax=4g+k(kmg+A)
=40+20=60N
Two bodies of masses 1 kg and 4 kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of…
JEE Main 2014 — Physics Waves & Oscillations
2014mcqhard
Two bodies of masses 1kg and 4kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25rads−1, and amplitude 1.6cm while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is (take g=10ms−2).
Official previous-year question
Held on 9 Apr 2014 · Verified 6 Jul 2026.
Options
- A
20N
- B
60N
- C
40N
- D
10N
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