l1:l2:l3=6:3:2
The frequancy in any nth mode for a segment is f=2lnv=constant
no of loops ∝ length of the segment
so, no of loops are in the ratio 6:3:2
hence total loops =11
The string is divided in 60 cm, 30 cm, & 20 cm part such that for minimum frequency, the wavelength is maximum
2λ=111x110=10cm
f=λV=λ1⋅μF=0.210.01400=1000Hz