JEE Main 2014 — Physics Waves & Oscillations
The total length of a sonometer wire fixed between two bridges is 110cm. Now, two more bridges are placed to divide the length of the wire in the ratio 6:3:2. If the tension in the wire is 400N and the mass per unit length of the wire is 0.01kgm−1, then the minimum common frequency with which all the three parts can vibrate, is
Held on 19 Apr 2014 · Verified 6 Jul 2026.
1000Hz
1100Hz
100Hz
110Hz
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In an open organ pipe $\nu_{3}$ and $\nu_{6}$ are $3^{\text {rd }}$ and $6^{\text {th }}$ harmonic frequencies, respectively. If $\nu_{6}-\nu_{3}=2200 \mathrm{~Hz}$ then length of the pipe is $\_\_\_\_$ mm . (Take velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$.)
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