f = V 2 ℓ = 1 2 ℓ T μ = 1 2 ℓ T Ad
Also, Y = T ℓ A Δ ℓ ⇒ T A = Y Δ ℓ ℓ ⇒ f = 1 2 ℓ Y Δ ℓ ℓ d
ℓ=1.5 m, ℓΔℓ=0.01, d=7.7×103kg/m3
Y=2.2×1011N/m2
After solving
f = 2 7 × 1 0 3 3 Hz
f ≈ 178.2 Hz
JEE Main 2013 — Physics Waves & Oscillations
A sonometer wire of length 1.5m is made of steel. The tension in it produces an elastic strain of \text{1%}. What is the fundamental frequency of steel if density and elasticity of steel are 7.7×103kgm−3 and 2.2×1011Nm−2 respectively?
Held on 7 Apr 2013 · Verified 6 Jul 2026.
200.5Hz
770Hz
188.5Hz
178.2Hz
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