Given : Frequency of tuning fork, n=264 Hz Length of column L= ? For closed organ pipe n=4lv⇒l=4nv=4×264330=0.3125 or, l=0.3125×100=31.25 cm In case of closed organ pipe only odd harmonics are possible. Therefore value of l will be (2n−1)l Hence option (b) i.e. 3×31.25=93.75 cm is correct.
An air column in a pipe, which is closed at one end, will be in resonance wtih a vibrating tuning fork of frequency 264 ~Hz if the length of the…
JEE Main 2012 — Physics Waves & Oscillations
2012mcqeasy
An air column in a pipe, which is closed at one end, will be in resonance wtih a vibrating tuning fork of frequency 264 Hz if the length of the column in cm is (velocity of sound =330 m/s )
Official previous-year question
Held on 26 May 2012 · Verified 6 Jul 2026.
Options
- A
125.00
- B
93.75
- C
62.50
- D
187.50
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