As we know,
f1=[μmμL−1][R11−R21]
For air μm=1
121=[1.6−1][R11−R21]121=106[R11−R21][R11−R21]=7210
For water
f1=[1.281.6−1][7210]=12832×7210
f1=41×7210f=28.8 cmf=288 mm
JEE Main 2025 — Physics Optics
A lens having refractive index 1.6 has focal length of 12 cm , when it is in air. Find the focal length of the lens when it is placed in water.
(Take refractive index of water as 1.28)
Held on 7 Apr 2025 · Verified 6 Jul 2026.
355 mm
288 mm
555 mm
655 mm
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