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A parallel plate capacitor having a separation between the plates d, plate area A and material with dielectric constant K has capacitance C_0. Now…

JEE Main 2013 — Physics Electromagnetism

2013mcqmedium

A parallel plate capacitor having a separation between the plates d\mathrm{d}d, plate area A\mathrm{A}A and material with dielectric constant K\mathrm{K}K has capacitance C0\mathrm{C}_0C0​. Now one-third of the material is replaced by another material with dielectric constant 2 K2 \mathrm{~K}2 K, so that effectively there are two capacitors one with area 13 A\frac{1}{3} \mathrm{~A}31​ A, dielectric constant 2 K2 \mathrm{~K}2 K and another with area 23 A\frac{2}{3} \mathrm{~A}32​ A and dielectric constant K\mathrm{K}K. If the capacitance of this new capacitor is C\mathrm{C}C then CC0\frac{\mathrm{C}}{\mathrm{C}_0}C0​C​ is

Official previous-year question

Held on 25 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    111

  2. B

    43\frac{4}{3}34​

  3. C

    23\frac{2}{3}32​

  4. D

    13\frac{1}{3}31​

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